What is the domain of sqrt(x(x+1)) ?

The domain of sqrt(x(x+1)) is x = 0

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domain of sqrt(x(x+1))

domain

x (x + 1)

x \leq - 1 or x \geq 0

Interval Notation

(- \infty, - 1] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 0

The function domain

x \leq - 1 or x \geq 0

(0, 0), (9, 12)

(3, - 3), (7, 3)

f (x) = \frac{5 y - 8}{11}

f (x) = \frac{- x + 2}{3}

f (x) = 25 - x^{2}

What is the domain of sqrt(x(x+1)) ?
The domain of sqrt(x(x+1)) is x<=-1\lor x>= 0