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Popular >

midpoint (3,-3),(7,3)

Solution

midpoint

(3, - 3), (7, 3)

Solution

(5, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 3), (x_{2}, y_{2}) = (7, 3)

= (\frac{7 + 3}{2}, \frac{3 - 3}{2})

Refine

= (5, 0)

Popular Examples

domain of f(x)=(5y-8)/(11)domain

f (x) = \frac{5 y - 8}{11}

inverse of f(x)=(-x+2)/3 inverse

f (x) = \frac{- x + 2}{3}

range of f(x)=25-x^2 range

f (x) = 25 - x^{2}

asymptotes of f(x)=(x^2-7x+12)/(x^2+x-6)asymptotes

f (x) = \frac{x ^{2} - 7 x + 12}{x ^{2} + x - 6}

asymptotes of f(x)=(x^2-4x+4)/(x^3-4x^2)asymptotes

f (x) = \frac{x ^{2} - 4 x + 4}{x ^{3} - 4 x ^{2}}

Frequently Asked Questions (FAQ)

What is the midpoint (3,-3),(7,3) ?
The midpoint (3,-3),(7,3) is (5,0)