What is the critical f(x)=(x-6)^{2/3} ?

The critical f(x)=(x-6)^{2/3} is x=6

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critical f(x)=(x-6)^{2/3}

critical points

f (x) = (x - 6)^{\frac{2}{3}}

x = 6

Solution steps

(x - 6)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 6

Identify critical points not in

f (x)

domain

Domain of

(x - 6)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = 6

f (x) = 15 cos (\frac{1}{2}) (x + \frac{π}{2})

f (x) = - x^{3} - x^{2} + 5 x - 1

f (x) = e^{(x^{3} - 6 x^{2} + 8)}

y = 2 x - 1, (1, 1)

y = \frac{1}{4} x