What is the perpendicular y=2x-1,(1,1) ?

The perpendicular y=2x-1,(1,1) is y=-1/2 x+3/2

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perpendicular y=2x-1,(1,1)

perpendicular

y = 2 x - 1, (1, 1)

y = - \frac{1}{2} x + \frac{3}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 2 x - 1

that passes through

(1, 1)

Find the slope of

y = 2 x - 1 : m = 2

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(1, 1) : y = - \frac{1}{2} x + \frac{3}{2}

y = - \frac{1}{2} x + \frac{3}{2}

y = \frac{1}{4} x

f (x) = x x^{2} - 1

ln (2 x - 1)

f (x) = x e - x

\frac{( 6 - 4 x ) ^{2}}{2 x ^{2} - 5 x + 12}

What is the perpendicular y=2x-1,(1,1) ?
The perpendicular y=2x-1,(1,1) is y=-1/2 x+3/2