What is the range of ln(2x-1) ?

The range of ln(2x-1) is -infinity <f(x)<infinity

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range of ln(2x-1)

range

ln (2 x - 1)

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of a logarithmic function of the form

c \cdot lo g (a x + b) + k

is all the real numbers

- \infty < f (x) < \infty

f (x) = x e - x

\frac{( 6 - 4 x ) ^{2}}{2 x ^{2} - 5 x + 12}

y = x^{2} + 6 x - 2

y = 4 x + 8

(1.3, 9), (1.5, 7)

What is the range of ln(2x-1) ?
The range of ln(2x-1) is -infinity <f(x)<infinity