What is the domain of (sqrt(1-x^2))/(2-x) ?

The domain of (sqrt(1-x^2))/(2-x) is -1<= x<= 1

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domain of (sqrt(1-x^2))/(2-x)

domain

\frac{1 - x ^{2}}{2 - x}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 1 \leq x \leq 1

f (x) = ln (x - 2)

y = arcsin (- \frac{1}{2} π)

\frac{- 3 x + 6}{x ^{2} - 4}

f (x) = lo g_{5} (\frac{x}{3})

10 x - 6 y = 66

What is the domain of (sqrt(1-x^2))/(2-x) ?
The domain of (sqrt(1-x^2))/(2-x) is -1<= x<= 1