What is the inverse of f(x)=(81)/(x^4) ?

The inverse of f(x)=(81)/(x^4) is (3x^{3/4})/x ,-(3x^{3/4})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(81)/(x^4)

inverse

f (x) = \frac{81}{x ^{4}}

\frac{3 x ^{\frac{3}{4}}}{x}, - \frac{3 x ^{\frac{3}{4}}}{x}

Solution steps

y = \frac{81}{x ^{4}}

Replace

x

with

y

x = \frac{81}{y ^{4}}

Solve for

y, x = \frac{81}{y ^{4}}

\frac{3 x ^{\frac{3}{4}}}{x}, - \frac{3 x ^{\frac{3}{4}}}{x}

f (x) = 4^{x}

f (x) = 5 x - 3

f (x) = \frac{x - 4}{4 x - 24}

f (x) = \frac{x ^{2} + 4}{x - 1}

f (x) = \frac{3}{x + 7}

What is the inverse of f(x)=(81)/(x^4) ?
The inverse of f(x)=(81)/(x^4) is (3x^{3/4})/x ,-(3x^{3/4})/x