en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (6,-2),(-1,0)

Solution

midpoint

(6, - 2), (- 1, 0)

Solution

(\frac{5}{2}, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (6, - 2), (x_{2}, y_{2}) = (- 1, 0)

= (\frac{- 1 + 6}{2}, \frac{0 - 2}{2})

Refine

= (\frac{5}{2}, - 1)

Popular Examples

domain of f(x)= 1/(\sqrt[4]{x^2-3x)}domain

asymptotes of f(x)=((7e^x))/(e^x-2)asymptotes

f (x) = \frac{( 7 e ^{x} )}{e ^{x} - 2}

critical f(x)=x^3-4x^2+x+6 critical points

f (x) = x^{3} - 4 x^{2} + x + 6

range of f(x)= x/(6-x)range

f (x) = \frac{x}{6 - x}

periodicity of y=cos(x-pi/2)periodicity

y = cos (x - \frac{π}{2})

Frequently Asked Questions (FAQ)

What is the midpoint (6,-2),(-1,0) ?
The midpoint (6,-2),(-1,0) is (5/2 ,-1)