What is the domain of f(x)= 1/(\sqrt[4]{x^2-3x)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-3x)} is x 3

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domain of f(x)= 1/(\sqrt[4]{x^2-3x)}

domain

x < 0 or x > 3

Interval Notation

(- \infty, 0) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 3

Find undefined (singularity) points:

x = 3, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 3

f (x) = \frac{( 7 e ^{x} )}{e ^{x} - 2}

f (x) = x^{3} - 4 x^{2} + x + 6

f (x) = \frac{x}{6 - x}

y = cos (x - \frac{π}{2})

f (x) = - 2 x^{4} + 7 x^{2}

What is the domain of f(x)= 1/(\sqrt[4]{x^2-3x)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-3x)} is x<0\lor x>3