What is the domain of f(x)=(sqrt(x))/(2x-1) ?

The domain of f(x)=(sqrt(x))/(2x-1) is 0 1/2

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domain of f(x)=(sqrt(x))/(2x-1)

domain

f (x) = \frac{x}{2 x - 1}

0 \leq x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

[0, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{2} or x > \frac{1}{2}

f (x) = - x^{2}

(- 4, - 18), (3, - 15)

3 x - 12

y + 3 = \frac{1}{2} (x + 4)

f (x) = 4 - 3 x

What is the domain of f(x)=(sqrt(x))/(2x-1) ?
The domain of f(x)=(sqrt(x))/(2x-1) is 0<= x< 1/2 \lor x> 1/2