What is the inverse of f(x)=3x^2+5 ?

The inverse of f(x)=3x^2+5 is sqrt((x-5)/3),-sqrt((x-5)/3)

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inverse of f(x)=3x^2+5

inverse

f (x) = 3 x^{2} + 5

\frac{x - 5}{3}, - \frac{x - 5}{3}

Solution steps

y = 3 x^{2} + 5

Replace

x

with

y

x = 3 y^{2} + 5

Solve for

y, x = 3 y^{2} + 5

\frac{x - 5}{3}, - \frac{x - 5}{3}

\frac{x ^{2} + x - 6}{- 4 x ^{2} - 16 x - 12}

y = \frac{1}{2} x + 4

x^{3} - 4 x

f (x) = 4 - 4 x

f (x) = 2, - 1 < x < 2

What is the inverse of f(x)=3x^2+5 ?
The inverse of f(x)=3x^2+5 is sqrt((x-5)/3),-sqrt((x-5)/3)