What is the domain of f(x)=(x+1)/(sqrt(x-7)) ?

The domain of f(x)=(x+1)/(sqrt(x-7)) is x>7

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domain of f(x)=(x+1)/(sqrt(x-7))

domain

f (x) = \frac{x + 1}{x - 7}

x > 7

Interval Notation

(7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 7

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

x > 7

f (x) = 2 x^{2} + 2

f (x) = x^{2} - 2 ln (x)

x^{2} - 6 x + 10

x^{3} + 7 x^{2} + 8 x - 16

f (x) = \frac{4}{x - 2}

What is the domain of f(x)=(x+1)/(sqrt(x-7)) ?
The domain of f(x)=(x+1)/(sqrt(x-7)) is x>7