What is the critical f(x)=x^2-2ln(x) ?

The critical f(x)=x^2-2ln(x) is x=1

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critical f(x)=x^2-2ln(x)

critical points

f (x) = x^{2} - 2 ln (x)

x = 1

Solution steps

x^{2} - 2 ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 2 ln (x) : x > 0

x^{2} - 2 ln (x)

is not defined at

x = - 1, x = 0

, therefore:

x = 1

x^{2} - 6 x + 10

x^{3} + 7 x^{2} + 8 x - 16

f (x) = \frac{4}{x - 2}

f (x) = cos^{2} (2 π x)

4 - 6 t