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Popular >

range of sin(2x)

Solution

range

sin (2 x)

Solution

- 1 \leq f (x) \leq 1

+1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (2 x) \leq 1

- 1 \leq sin (2 x) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

Popular Examples

domain of f(x)=(sqrt(x+6))/(x-9)domain

f (x) = \frac{x + 6}{x - 9}

inverse of 18500(0.09-x^2)inverse

18500 (0.09 - x^{2})

range of y=((5x-3))/(2x+6)range

y = \frac{( 5 x - 3 )}{2 x + 6}

domain of arccsc(x+7)domain

arccsc (x + 7)

inverse of f(x)=-3sqrt(x+2)-6 inverse

f (x) = - 3 x + 2 - 6

Frequently Asked Questions (FAQ)

What is the range of sin(2x) ?
The range of sin(2x) is -1<= f(x)<= 1