What is the domain of f(x)=(sqrt(x+6))/(x-9) ?

The domain of f(x)=(sqrt(x+6))/(x-9) is -6 9

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domain of f(x)=(sqrt(x+6))/(x-9)

domain

f (x) = \frac{x + 6}{x - 9}

- 6 \leq x < 9 or x > 9

Interval Notation

[- 6, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 6 \leq x < 9 or x > 9

18500 (0.09 - x^{2})

y = \frac{( 5 x - 3 )}{2 x + 6}

arccsc (x + 7)

f (x) = - 3 x + 2 - 6

\frac{x - 4}{3 x - x ^{2}}

What is the domain of f(x)=(sqrt(x+6))/(x-9) ?
The domain of f(x)=(sqrt(x+6))/(x-9) is -6<= x<9\lor x>9