What is the domain of f(x)=sqrt(-x^3-2x^2+16x+32) ?

The domain of f(x)=sqrt(-x^3-2x^2+16x+32) is x<=-4\lor-2<= x<= 4

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domain of f(x)=sqrt(-x^3-2x^2+16x+32)

domain

f (x) = - x^{3} - 2 x^{2} + 16 x + 32

x \leq - 4 or - 2 \leq x \leq 4

Interval Notation

(- \infty, - 4] \cup [- 2, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 4 or - 2 \leq x \leq 4

The function domain

x \leq - 4 or - 2 \leq x \leq 4

(0, - 3), (- 10, - 7)

f (x) = x^{3} + 3 x^{2} + 2

f (x) = \frac{1 + x ^{2}}{4}

f (x) = \frac{4 + x}{1 - x}

\frac{x - 3}{x + 5}

What is the domain of f(x)=sqrt(-x^3-2x^2+16x+32) ?
The domain of f(x)=sqrt(-x^3-2x^2+16x+32) is x<=-4\lor-2<= x<= 4