What is the inverse of f(x)= 2/3 (x-2)^3+6 ?

The inverse of f(x)= 2/3 (x-2)^3+6 is \sqrt[3]{(3x-18)/2}+2

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inverse of f(x)= 2/3 (x-2)^3+6

inverse

f (x) = \frac{2}{3} (x - 2)^{3} + 6

Solution steps

y = \frac{2}{3} (x - 2)^{3} + 6

Replace

x

with

y

x = \frac{2}{3} (y - 2)^{3} + 6

Solve for

y, x = \frac{2}{3} (y - 2)^{3} + 6

f (x) = 6 x - 6 x

f (x) = \frac{x ( x + 1 ) ( x - 3 )}{x ^{3}}

f (x) = lo g_{5} (x + 1)

f (x) = \frac{2 x - 3}{4 + 5 x} - 1

(d, c), (0, 0)

What is the inverse of f(x)= 2/3 (x-2)^3+6 ?
The inverse of f(x)= 2/3 (x-2)^3+6 is \sqrt[3]{(3x-18)/2}+2