What is the inverse of f(x)=((x-10)^{1/3})/7 ?

The inverse of f(x)=((x-10)^{1/3})/7 is 343x^3+10

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inverse of f(x)=((x-10)^{1/3})/7

inverse

f (x) = \frac{( x - 10 ) ^{\frac{1}{3}}}{7}

343 x^{3} + 10

Solution steps

y = \frac{( x - 10 ) ^{\frac{1}{3}}}{7}

Replace

x

with

y

x = \frac{( y - 10 ) ^{\frac{1}{3}}}{7}

Solve for

y, x = \frac{( y - 10 ) ^{\frac{1}{3}}}{7}

343 x^{3} + 10

f (x) = \frac{x - 1}{x ^{2} - 9}

\frac{3 x ^{2} - 27}{x ^{2} + 6 x + 9}

f (x) = x^{2} - 1, x \geq 0

f (x) = \frac{x + 5}{2}

6 x + y = - 1

What is the inverse of f(x)=((x-10)^{1/3})/7 ?
The inverse of f(x)=((x-10)^{1/3})/7 is 343x^3+10