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Popular >

extreme f(x)=x^2+2x-4

Solution

extreme points

f (x) = x^{2} + 2 x - 4

Solution

Minimum (- 1, - 5)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x - 4 : - 5

Minimum (- 1, - 5)

Popular Examples

range of f(x)=e^{(-5x-1/5)}+5 range

f (x) = e^{(- 5 x - \frac{1}{5})} + 5

inverse of f(x)=log_{2}(x-1)+3 inverse

f (x) = lo g_{2} (x - 1) + 3

inverse of ((x+5))/((x+6))inverse

\frac{( x + 5 )}{( x + 6 )}

domain of sqrt(5x+10)domain

5 x + 10

inverse of f(x)=x^2-16x,x>= 8 inverse

f (x) = x^{2} - 16 x, x \geq 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x-4 ?
The extreme f(x)=x^2+2x-4 is Minimum(-1,-5)