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Popular >

range of f(x)=(2x^2-3)/5

Solution

range

f (x) = \frac{2 x ^{2} - 3}{5}

Solution

f (x) \geq - \frac{3}{5}

+1

Interval Notation

[- \frac{3}{5}, \infty)

Solution steps

Vertex of

\frac{2 x ^{2} - 3}{5} :

Minimum

(0, - \frac{3}{5})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = \frac{2}{5},

Vertex

(x_{v}, y_{v}) = (0, - \frac{3}{5})

f (x) \geq - \frac{3}{5}

Popular Examples

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4 cos (\frac{x}{2})

parity sqrt(x)parity

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inverse of (3x)/(x+2)inverse

\frac{3 x}{x + 2}

slope of 5y-x=10 slope

5 y - x = 10

extreme f(x)=4x^3-7x^2-2x+4 extreme points

f (x) = 4 x^{3} - 7 x^{2} - 2 x + 4

Frequently Asked Questions (FAQ)

What is the range of f(x)=(2x^2-3)/5 ?
The range of f(x)=(2x^2-3)/5 is f(x)>=-3/5