What is the inverse of f(x)=2(x+3)^3+1 ?

The inverse of f(x)=2(x+3)^3+1 is \sqrt[3]{(x-1)/2}-3

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inverse of f(x)=2(x+3)^3+1

inverse

f (x) = 2 (x + 3)^{3} + 1

Solution steps

y = 2 (x + 3)^{3} + 1

Replace

x

with

y

x = 2 (y + 3)^{3} + 1

Solve for

y, x = 2 (y + 3)^{3} + 1

f (x) = \frac{( x + 5 ) ( 4 x + 3 )}{x ^{2} - 4}

f (t) = 2 sin (t + 3) + 1

lo g_{5} (x - 3)

3 e^{- 2 x}

(0, \frac{1}{5}), (- \frac{6}{7}, 0)

What is the inverse of f(x)=2(x+3)^3+1 ?
The inverse of f(x)=2(x+3)^3+1 is \sqrt[3]{(x-1)/2}-3