What is the perpendicular 3x+6y=12 ?

The perpendicular 3x+6y=12 is y=2x+b

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perpendicular 3x+6y=12

perpendicular

3 x + 6 y = 12

y = 2 x + b

Solution steps

Find the slope of

3 x + 6 y = 12 : m = - \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = 2

Line with slope m=

2 : y = 2 x + b

y = 2 x + b

e^{x} - 1

f (x) = lo g_{2} (x) + 1

(- 1, 0), (2, 1)

\frac{3 x ^{2} - 18 x + 24}{x ^{2} - 4 x}

\frac{x}{x - 4}