What is the domain of f(x)= 1/(sqrt(6x-12)) ?

The domain of f(x)= 1/(sqrt(6x-12)) is x>2

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domain of f(x)= 1/(sqrt(6x-12))

domain

f (x) = \frac{1}{6 x - 12}

x > 2

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{7 x}{5 + 3 x}

x^{3} - x^{2} + 2 x - 1

f (x) = 6 t^{\frac{2}{3}} + t^{\frac{5}{3}}

f (x) = 2 cos (π x)

\frac{7}{x - 5}

What is the domain of f(x)= 1/(sqrt(6x-12)) ?
The domain of f(x)= 1/(sqrt(6x-12)) is x>2