What is the domain of f(x)=sqrt(x-1)+sqrt(4-x) ?

The domain of f(x)=sqrt(x-1)+sqrt(4-x) is 1<= x<= 4

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domain of f(x)=sqrt(x-1)+sqrt(4-x)

domain

f (x) = x - 1 + 4 - x

1 \leq x \leq 4

Interval Notation

[1, 4]

Solution steps

Find non-negative values for radicals:

1 \leq x \leq 4

The function domain

1 \leq x \leq 4

f (x) = \frac{2 x}{( x - 2 ) ( x + 1 )}

m = 2, (3, - 4)

f (x) = 2^{\frac{x}{2}} + 5

y = x + 5

y = 2 x - 5

What is the domain of f(x)=sqrt(x-1)+sqrt(4-x) ?
The domain of f(x)=sqrt(x-1)+sqrt(4-x) is 1<= x<= 4