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Popular >

distance (2,4),(6,8)

Solution

distance

(2, 4), (6, 8)

Solution

42

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 4)

and

(6, 8)

is

= (6 - 2)^{2} + (8 - 4)^{2}

Simplify

= 42

Popular Examples

slope ofintercept y+3=-2/3 (x-2)slope intercept

y + 3 = - \frac{2}{3} (x - 2)

domain of 4/(x-5)+2 domain

\frac{4}{x - 5} + 2

asymptotes of f(x)=(x^2-9x-10)/(2x+2)asymptotes

f (x) = \frac{x ^{2} - 9 x - 10}{2 x + 2}

asymptotes of (x^2-2x-35)/(x^2-16)asymptotes

\frac{x ^{2} - 2 x - 35}{x ^{2} - 16}

inflection f(x)=3-5x^4 inflection points

f (x) = 3 - 5 x^{4}

Frequently Asked Questions (FAQ)

What is the distance (2,4),(6,8) ?
The distance (2,4),(6,8) is 4sqrt(2)