What is the critical f(x)=5+1/4 x-1/2 x^2 ?

The critical f(x)=5+1/4 x-1/2 x^2 is x= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=5+1/4 x-1/2 x^2

critical points

f (x) = 5 + \frac{1}{4} x - \frac{1}{2} x^{2}

x = \frac{1}{4}

Solution steps

5 + \frac{1}{4} x - \frac{1}{2} x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{4}

Identify critical points not in

f (x)

domain

Domain of

5 + \frac{1}{4} x - \frac{1}{2} x^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{4}

\frac{1}{x - 6}

y = x^{2} - 3

f (x) = e^{x} + 4

f (x) = e^{x} - e^{(- x)}

y = 3 cos (x - 1) - 3

What is the critical f(x)=5+1/4 x-1/2 x^2 ?
The critical f(x)=5+1/4 x-1/2 x^2 is x= 1/4