What is the range of f(x)=sqrt(2x-3) ?

The range of f(x)=sqrt(2x-3) is f(x)>= 0

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range of f(x)=sqrt(2x-3)

range

f (x) = 2 x - 3

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = - 0.1 (x - 4)^{2} + 4.2

2 (1)^{4} - 11 (1)^{2}

f (x) = \frac{( x + 3 )}{( x - 8 )}

f (x) = 5 x - 4 y = 20

- \frac{2}{3}