What is the extreme f(x)=x^2e^x-4 ?

The extreme f(x)=x^2e^x-4 is Maximum(-2, 4/(e^2)-4),Minimum(0,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2e^x-4

extreme points

f (x) = x^{2} e^{x} - 4

Maximum (- 2, \frac{4}{e ^{2}} - 4), Minimum (0, - 4)

Solution steps

f^{'} (x) = e^{x} x^{2} + 2 e^{x} x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{2} e^{x} - 4 : \frac{4}{e ^{2}} - 4

Maximum (- 2, \frac{4}{e ^{2}} - 4)

Plug

x = 0

into

x^{2} e^{x} - 4 : - 4

Minimum (0, - 4)

Maximum (- 2, \frac{4}{e ^{2}} - 4), Minimum (0, - 4)

3 x + y = 8

f (x) = \frac{- x ^{2}}{x ^{2} - 2 x + 8}

f (x) = \frac{( 2 x + 4 )}{3}

- 7 x - 2 y = 14

f (x) = - 2^{x}

What is the extreme f(x)=x^2e^x-4 ?
The extreme f(x)=x^2e^x-4 is Maximum(-2, 4/(e^2)-4),Minimum(0,-4)