What is the range of f(x)= 4/(sqrt(1-3x)) ?

The range of f(x)= 4/(sqrt(1-3x)) is f(x)>0

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range of f(x)= 4/(sqrt(1-3x))

range

f (x) = \frac{4}{1 - 3 x}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{4}{1 - 3 x} : x < \frac{1}{3}

Extreme Points of

\frac{4}{1 - 3 x} :

None

Find the range for the interval

- \infty < x < \frac{1}{3} : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

f (x) = - 3 x^{2} - 12 x - 9

\frac{x ^{3} + 5}{x ^{5} + 2}

y = \frac{3}{4} x - \frac{31}{4}, (1, 0)

f (x) = - (- 12 x + 13)^{2} - 1

f (x) = \frac{x ^{2} - 2 x - 48}{x + 6}

What is the range of f(x)= 4/(sqrt(1-3x)) ?
The range of f(x)= 4/(sqrt(1-3x)) is f(x)>0