What is the domain of 1/(10(sqrt(2x+12))-20) ?

The domain of 1/(10(sqrt(2x+12))-20) is -6 -4

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domain of 1/(10(sqrt(2x+12))-20)

domain

\frac{1}{10 ( 2 x + 12 ) - 20}

- 6 \leq x < - 4 or x > - 4

Interval Notation

[- 6, - 4) \cup (- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

- 6 \leq x < - 4 or x > - 4

f (x) = - 5^{x}

\frac{4 x - 1}{2 x + 3}

f (x) = x^{2} - 3 x - 28

f (x) = 2 x

y - 2 = - 5 (x + 1)

What is the domain of 1/(10(sqrt(2x+12))-20) ?
The domain of 1/(10(sqrt(2x+12))-20) is -6<= x<-4\lor x>-4