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Popular >

midpoint (-5,-2),(-8,-5)

Solution

midpoint

(- 5, - 2), (- 8, - 5)

Solution

(- \frac{13}{2}, - \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 5, - 2), (x_{2}, y_{2}) = (- 8, - 5)

= (\frac{- 8 - 5}{2}, \frac{- 5 - 2}{2})

Refine

= (- \frac{13}{2}, - \frac{7}{2})

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f (x) = \frac{4 x}{x ^{2} + 3 x - 10}

range of arctan(x)range

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range of 7+sqrt(6+x)range

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Frequently Asked Questions (FAQ)

What is the midpoint (-5,-2),(-8,-5) ?
The midpoint (-5,-2),(-8,-5) is (-13/2 ,-7/2)