What is the range of 7/(sqrt(x+5)) ?

The range of 7/(sqrt(x+5)) is f(x)>0

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range of 7/(sqrt(x+5))

range

\frac{7}{x + 5}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{7}{x + 5} : x > - 5

Extreme Points of

\frac{7}{x + 5} :

None

Find the range for the interval

- 5 < x < \infty : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

a^{x}

y = x + 1

(0, 4), (- 4, 0)

f (x) = 2 e^{x}

y = sec (x)