What is the domain of f(x)=sqrt(4x+4) ?

The domain of f(x)=sqrt(4x+4) is x>=-1

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domain of f(x)=sqrt(4x+4)

domain

f (x) = 4 x + 4

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = 15 - x^{2}, x \geq 0

f (x) = 5 x + \frac{2}{x}

f (x) = 8 x - 2

y = - 3 x + 2

1 + \frac{1}{x - 1}