What is the domain of f(x)= 1/(sqrt(3x+6)) ?

The domain of f(x)= 1/(sqrt(3x+6)) is x>-2

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domain of f(x)= 1/(sqrt(3x+6))

domain

f (x) = \frac{1}{3 x + 6}

x > - 2

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

x^{3} - 27

f (x) = \frac{x + 1}{x - 5}

(- 2, 8), (4, 6)

x \cdot x

f (x) = \frac{2 x ^{2} - 6 x + 2}{( 2 x - 3 ) ^{2}}

What is the domain of f(x)= 1/(sqrt(3x+6)) ?
The domain of f(x)= 1/(sqrt(3x+6)) is x>-2