What is the domain of f(x)= 1/((x-3)(x-5)) ?

The domain of f(x)= 1/((x-3)(x-5)) is x 5

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domain of f(x)= 1/((x-3)(x-5))

domain

f (x) = \frac{1}{( x - 3 ) ( x - 5 )}

x < 3 or 3 < x < 5 or x > 5

Interval Notation

(- \infty, 3) \cup (3, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 5

The function domain

x < 3 or 3 < x < 5 or x > 5

f (x) = 3 x - 15

f (x) = 6 e^{x - 4}

f (x) = 2 (x - 3)^{2} - 2

2 x + 5

\frac{1}{x ^{2} - 16}

What is the domain of f(x)= 1/((x-3)(x-5)) ?
The domain of f(x)= 1/((x-3)(x-5)) is x<3\lor 3<x<5\lor x>5