What is the extreme 4x(x^2-9) ?

The extreme 4x(x^2-9) is Maximum(-sqrt(3),24sqrt(3)),Minimum(sqrt(3),-24sqrt(3))

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extreme 4x(x^2-9)

extreme points

4 x (x^{2} - 9)

Maximum (- 3, 243), Minimum (3, - 243)

Solution steps

f^{'} (x) = 4 (3 x^{2} - 9)

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

4 x (x^{2} - 9) : 243

Maximum (- 3, 243)

Plug

x = 3

into

4 x (x^{2} - 9) : - 243

Minimum (3, - 243)

Maximum (- 3, 243), Minimum (3, - 243)

y = (\frac{1}{2})^{4 - 3 x} - 7

f (t) = \frac{4 - t ^{2}}{2 - t}

- \frac{3}{2} sin (2 x - \frac{3 π}{4}) + \frac{7}{3}

f (x) = (0, - 5) (5, 0)

f (x) = 2 (2)^{4} - 16 (2)^{3} + 8

What is the extreme 4x(x^2-9) ?
The extreme 4x(x^2-9) is Maximum(-sqrt(3),24sqrt(3)),Minimum(sqrt(3),-24sqrt(3))