What is the domain of f(x)= 1/(x^2-25) ?

The domain of f(x)= 1/(x^2-25) is x 5

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domain of f(x)= 1/(x^2-25)

domain

f (x) = \frac{1}{x ^{2} - 25}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = \frac{6 x + 1}{x - 4}

tan (\frac{arcsin ( \frac{x}{10} )}{2})

f (x) = - 4 - x + x^{2}

f (x) = x^{2} (4 - 4 x)^{2}

f (x) = 3 x^{2} - 24 x + 9, 0 \leq x \leq 9

What is the domain of f(x)= 1/(x^2-25) ?
The domain of f(x)= 1/(x^2-25) is x<-5\lor-5<x<5\lor x>5