What is the inverse of f(x)=x^2-5x ?

The inverse of f(x)=x^2-5x is (5+sqrt(25+4x))/2 ,(5-sqrt(25+4x))/2

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inverse of f(x)=x^2-5x

inverse

f (x) = x^{2} - 5 x

\frac{5 + 25 + 4 x}{2}, \frac{5 - 25 + 4 x}{2}

Solution steps

y = x^{2} - 5 x

Replace

x

with

y

x = y^{2} - 5 y

Solve for

y, x = y^{2} - 5 y

\frac{5 + 25 + 4 x}{2}, \frac{5 - 25 + 4 x}{2}

f (x) = x - 9 + x + 14

f (x) = - 3 x + 4

f (x) = x^{2} + 9, x \geq 0

f (x) = x + x + 5

f (x) = ln (9 x^{2} + 1)

What is the inverse of f(x)=x^2-5x ?
The inverse of f(x)=x^2-5x is (5+sqrt(25+4x))/2 ,(5-sqrt(25+4x))/2