What is the range of f(x)=((8x-3))/x ?

The range of f(x)=((8x-3))/x is f(x) 8

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range of f(x)=((8x-3))/x

range

f (x) = \frac{( 8 x - 3 )}{x}

f (x) < 8 or f (x) > 8

Interval Notation

(- \infty, 8) \cup (8, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{8 x - 3}{x}

Inverse of

\frac{8 x - 3}{x} : - \frac{3}{x - 8}

- \frac{3}{x - 8}

Find the domain of each inverse function

Domain of

- \frac{3}{x - 8} : x < 8 or x > 8

Combine the intervals

f (x) < 8 or f (x) > 8

f (x) = \frac{x}{25 - x ^{2}}

f (x) = x^{2}

f (x) = x^{2} - 4

f (x) = \frac{1}{x ^{2} - x - 6}

f (x) = x e^{- 4 π x}

What is the range of f(x)=((8x-3))/x ?
The range of f(x)=((8x-3))/x is f(x)<8\lor f(x)>8