What is the perpendicular y=2.5x,(2,5) ?

The perpendicular y=2.5x,(2,5) is y=-2/5 x+29/5

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perpendicular y=2.5x,(2,5)

perpendicular

y = 2.5 x, (2, 5)

y = - \frac{2}{5} x + \frac{29}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 2.5 x

that passes through

(2, 5)

Find the slope of

y = 2.5 x : m = 2.5

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{5}

Find the line with slope m=

- \frac{2}{5}

and passing through

(2, 5) : y = - \frac{2}{5} x + \frac{29}{5}

y = - \frac{2}{5} x + \frac{29}{5}

f (x) = x 4 - x^{2}

y = - x^{6}

lo g_{10} (x^{2})

x^{4} - 8 x^{3}

f (x) = x^{4} + 6

What is the perpendicular y=2.5x,(2,5) ?
The perpendicular y=2.5x,(2,5) is y=-2/5 x+29/5