What is the perpendicular y= 4/3 x+6,(-4,-1) ?

The perpendicular y= 4/3 x+6,(-4,-1) is y=-3/4 x-4

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perpendicular y= 4/3 x+6,(-4,-1)

perpendicular

y = \frac{4}{3} x + 6, (- 4, - 1)

y = - \frac{3}{4} x - 4

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{4}{3} x + 6

that passes through

(- 4, - 1)

Find the slope of

y = \frac{4}{3} x + 6 : m = \frac{4}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(- 4, - 1) : y = - \frac{3}{4} x - 4

y = - \frac{3}{4} x - 4

f (x) = \frac{x ^{2} - 3 x - 4}{x - 4}

x^{3} + 2 x^{2} - x - 2

f (x) = x^{2} - 49

(\frac{1}{x - 4}) (\frac{1}{6 - x})

f (x) = x e^{- x}

What is the perpendicular y= 4/3 x+6,(-4,-1) ?
The perpendicular y= 4/3 x+6,(-4,-1) is y=-3/4 x-4