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Popular >

range of-(x-7)^2+4

Solution

range

- (x - 7)^{2} + 4

Solution

f (x) \leq 4

+1

Solution steps

Vertex of

- (x - 7)^{2} + 4 :

Maximum

(7, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (7, 4)

f (x) \leq 4

Popular Examples

simplify (8.5)(0.3)simplify

(8.5) (0.3)

intercepts of f(x)=-1/4 x^2+2x-1 intercepts

f (x) = - \frac{1}{4} x^{2} + 2 x - 1

domain of y=((x+9)(x-9))/(x^2+81)domain

y = \frac{( x + 9 ) ( x - 9 )}{x ^{2} + 81}

range of (x+6)/(4-sqrt(x^2-9))range

\frac{x + 6}{4 - x ^{2} - 9}

domain of f(x)=sqrt(x^4-4x^2+4)domain

f (x) = x^{4} - 4 x^{2} + 4

Frequently Asked Questions (FAQ)

What is the range of-(x-7)^2+4 ?
The range of-(x-7)^2+4 is f(x)<= 4