对称性 y=(x+1)^2-9

解答

对称性

y = (x + 1)^{2} - 9

y = - 1

求解步骤

y = (x + 1)^{2} - 9

改写为标准形式:

y = x^{2} + 2 x - 8

y = x^{2} + 2 x - 8

y = a x^{2} + b x + c

的对称轴是

x = \frac{- b}{2 a}

a = 1, b = 2

y = \frac{- 2}{2 \cdot 1}

整理后得

y = - 1

f (x) = 3

3 - e^{x}

lo g_{8} (x)

f (x) = \frac{x + 3}{x ^{2} + 7 x + 12}

(x, 2 x e^{x}), (0, 0)