What is the asymptotes of f(x)=(2x+4)/(x^2+2x-8) ?

The asymptotes of f(x)=(2x+4)/(x^2+2x-8) is Vertical: x=-4,x=2,Horizontal: y=0

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asymptotes of f(x)=(2x+4)/(x^2+2x-8)

asymptotes

f (x) = \frac{2 x + 4}{x ^{2} + 2 x - 8}

Vertical : x = - 4, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x + 4}{x ^{2} + 2 x - 8} : x = - 4, x = 2

Horizontal Asymptotes of

\frac{2 x + 4}{x ^{2} + 2 x - 8} : y = 0

Slant Asymptotes of

\frac{2 x + 4}{x ^{2} + 2 x - 8} :

None

Vertical : x = - 4, x = 2, Horizontal : y = 0

f (x) = 2 cos (3 x - π)

f (x) = \frac{37}{( 1 - 6 x ) ^{2}}

y = 3 x + 4

f (x) = (x + 1)^{2} + 9

\frac{9}{8}

What is the asymptotes of f(x)=(2x+4)/(x^2+2x-8) ?
The asymptotes of f(x)=(2x+4)/(x^2+2x-8) is Vertical: x=-4,x=2,Horizontal: y=0