What is the range of f(x)=4\sqrt[3]{2x+5}+10 ?

The range of f(x)=4\sqrt[3]{2x+5}+10 is -infinity <f(x)<infinity

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range of f(x)=4\sqrt[3]{2x+5}+10

range

- \infty < f (x) < \infty

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

Inverse of

\frac{- 1320 + x ^{3} - 30 x ^{2} + 300 x}{128}

Find the domain of each inverse function

Domain of

\frac{- 1320 + x ^{3} - 30 x ^{2} + 300 x}{128} : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

f (x) = \frac{2}{1 - e ^{x + 2}}

f (x) = 9 - x^{2} \cdot x + 1

3 x^{4} + 4 x^{3}

f (x) = \frac{x - 1}{( x + 3 ) ( x - 2 )}

f (x) = 1 0^{(x - 2)} - 5

What is the range of f(x)=4\sqrt[3]{2x+5}+10 ?
The range of f(x)=4\sqrt[3]{2x+5}+10 is -infinity <f(x)<infinity