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Popular >

midpoint (2,-7),(2,1)

Solution

midpoint

(2, - 7), (2, 1)

Solution

(2, - 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 7), (x_{2}, y_{2}) = (2, 1)

= (\frac{2 + 2}{2}, \frac{1 - 7}{2})

Refine

= (2, - 3)

Popular Examples

symmetry-2x^2+16x-31 symmetry

- 2 x^{2} + 16 x - 31

inverse of f(x)=(4x+5)^{1/5}inverse

f (x) = (4 x + 5)^{\frac{1}{5}}

domain of y=((x^2))/(1-x)domain

y = \frac{( x ^{2} )}{1 - x}

inverse of f(x)=-7/x inverse

f (x) = - \frac{7}{x}

domain of tan(pi/5 x)domain

tan (\frac{π}{5} x)

Frequently Asked Questions (FAQ)

What is the midpoint (2,-7),(2,1) ?
The midpoint (2,-7),(2,1) is (2,-3)