What is the domain of f(x)= 2/(1-x^2) ?

The domain of f(x)= 2/(1-x^2) is x 1

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domain of f(x)= 2/(1-x^2)

domain

f (x) = \frac{2}{1 - x ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = ln (3 x + 2)

(14, - 2), (7, - 8)

f (x) = (x - 9)^{3}

\frac{4 x ^{2} + 1}{x ^{2} + x + 16}

(2.3) (4.5)

What is the domain of f(x)= 2/(1-x^2) ?
The domain of f(x)= 2/(1-x^2) is x<-1\lor-1<x<1\lor x>1