What is the domain of f(x)= 1/(x^2+4)-1/(x^2-4) ?

The domain of f(x)= 1/(x^2+4)-1/(x^2-4) is x 2

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domain of f(x)= 1/(x^2+4)-1/(x^2-4)

domain

f (x) = \frac{1}{x ^{2} + 4} - \frac{1}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = \frac{2}{x + 5}

y = 8 x + 7

f (x) = 4 \cdot x^{2} - 3 \cdot x - 12

f (x) = 3 x^{3} - 18 x^{2} + 100

2 x + 3 y = 18

What is the domain of f(x)= 1/(x^2+4)-1/(x^2-4) ?
The domain of f(x)= 1/(x^2+4)-1/(x^2-4) is x<-2\lor-2<x<2\lor x>2