What is the domain of f(x)= 1/(x+9) ?

The domain of f(x)= 1/(x+9) is x -9

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domain of f(x)= 1/(x+9)

domain

f (x) = \frac{1}{x + 9}

x < - 9 or x > - 9

Interval Notation

(- \infty, - 9) \cup (- 9, \infty)

Solution steps

Find undefined (singularity) points:

x = - 9

The function domain

x < - 9 or x > - 9

y = cos (sin (tan (5 x)))

\frac{1}{2}

f (x) = x^{\frac{4}{5}}

3 x^{3} - 14

f (x) = \frac{x ^{2} - 3 x + 7}{x + 2}

What is the domain of f(x)= 1/(x+9) ?
The domain of f(x)= 1/(x+9) is x<-9\lor x>-9