What is the extreme f(x)=x^3+9x^2+24x ?

The extreme f(x)=x^3+9x^2+24x is Maximum(-4,-16),Minimum(-2,-20)

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extreme f(x)=x^3+9x^2+24x

extreme points

f (x) = x^{3} + 9 x^{2} + 24 x

Maximum (- 4, - 16), Minimum (- 2, - 20)

Solution steps

f^{'} (x) = 3 x^{2} + 18 x + 24

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 4

into

x^{3} + 9 x^{2} + 24 x : - 16

Maximum (- 4, - 16)

Plug

x = - 2

into

x^{3} + 9 x^{2} + 24 x : - 20

Minimum (- 2, - 20)

Maximum (- 4, - 16), Minimum (- 2, - 20)

f (x, y) = 1 - x^{2}

f (x) = 3 x

f (x) = 4 x 2 x^{2} + 1

f (x) = \frac{18}{x} - 1

What is the extreme f(x)=x^3+9x^2+24x ?
The extreme f(x)=x^3+9x^2+24x is Maximum(-4,-16),Minimum(-2,-20)